X=10t^2-40t+55

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Solution for X=10t^2-40t+55 equation: 



X=10X^2-40X+55

We move all terms to the left:

X-(10X^2-40X+55)=0

We get rid of parentheses

-10X^2+X+40X-55=0

We add all the numbers together, and all the variables

-10X^2+41X-55=0

a = -10; b = 41; c = -55;
Δ = b2-4ac
Δ = 412-4·(-10)·(-55)
Δ = -519
Delta is less than zero, so there is no solution for the equation

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